If (3x-2) is a factor of 3x^3+kx^2-21x+10. Find the value of k and factorise this completely
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Answer:
Step-by-step explanation:
f(x)=3x³+kx²-21x+10
g(x)=3x-2
so, x=2/3
f(2/3)=3*(2/3)³+k*(2/3)²-21*(2/3)+10=0
=3*8/27+k*4/9-14+10=0
=8/9+4k/9-4=0
=8/9+4k/9=4
=4k/9=4-8/9
=4k/9=28/9
=k=28/9*9/4
=k=7
so. k=7
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