Question

IF (3x-2) is
Find the value of
factor of
3n²-kn²t21n-10
K​

Answer 1

3x - 2 is a factor of eqn 3n^2 - kn^2 + 21n - 10

x = 2/3 is a root of equation

3(2/3)^2 - k(2/3)^2 + 21 (2/3) - 10 = 0

4/3 - k 4/9 + 41/3 - 10 = 0

4/3 - 4k/9 + 31/3 = 0

34/3 - 4k/9 =0

102/ 9 - 4k/ 9 = 0

4k = 102

k = 102 / 4