if 3x^2+xy-2y^2=0 and 2x^2-3xy+y^2=-1 then (x,y)
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Answer:
3x + 2y - 1
=(3) 2 + (2) -2 - 1
=6 - 4 - 1
=2 - 1
= 1
ok please mark a brainliest
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