Question

if 3x^2+xy-2y^2=0 and 2x^2-3xy+y^2=-1 then (x,y)

Answer 1

Answer:

3x + 2y - 1

=(3) 2 + (2) -2 - 1

=6 - 4 - 1

=2 - 1

= 1

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Step-by-step explanation: