Math, asked by banupriya3410, 1 year ago

if 3x + 2 y =12 and xy =6 find 9x^2 +4y^2

Answers

Answered by kiki9876
3
(3X+2Y)^2=9X^2+4Y^2+12XY
    12^2 =9X^2+4Y^2+12(6)
144-72=9X^2+4Y^2
9X^2+4Y^2=72
Answered by dfgh4
6
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