Question

If 3x+24>812 , then which numbers are possible values of x?

Answer 1

$3x + 24 > 812 \\ 3x > 812 - 24 \\ 3x > 788 \\ x > \frac{788}{3} \\ in \: \: interval \: \: form \\ x \in( \frac{788}{3} \:, \: \infty )$