If 3x-2y=11 and xy=12 find the value of 27x whole cube-8y whole cube
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Answered by
118
Hi...☺
Here is your answer...✌
GIVEN THAT,
3x - 2y = 11 -----(1)
xy = 12 -----(2)
Cubing both sides in eq(1)
We get
(3x - 2y)³ = 11³
(3x)³ - (2y)³ - 3(3x)(2y) (3x - 2y) = 11³
27x³ - 8y³ - 18xy × 11 = 11³ __ [from (1)]
27x³ - 8y³ - 18×12×11 = 11³ __ [from(2)]
27x³ - 8y³ = 11³ + 18×12×11
= 11 (11² + 18×12)
= 11 (121 + 216)
= 11 × 337
= 3707
Hence,
27x³ - 8y³ = 3707
Here is your answer...✌
GIVEN THAT,
3x - 2y = 11 -----(1)
xy = 12 -----(2)
Cubing both sides in eq(1)
We get
(3x - 2y)³ = 11³
(3x)³ - (2y)³ - 3(3x)(2y) (3x - 2y) = 11³
27x³ - 8y³ - 18xy × 11 = 11³ __ [from (1)]
27x³ - 8y³ - 18×12×11 = 11³ __ [from(2)]
27x³ - 8y³ = 11³ + 18×12×11
= 11 (11² + 18×12)
= 11 (121 + 216)
= 11 × 337
= 3707
Hence,
27x³ - 8y³ = 3707
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