Math, asked by sw47h1, 1 year ago



If 3x – 2y = 11 and xy = 12, Find the value of 27x3 – 8y3

Answers

Answered by Anonymous
29
Heya ✋

Let see your answer !!!!

Given that

3x - 2y = 11 ; xy = 12

27x ^{3}  - 8y ^{3}  =
3x - 2y = 11

On squaring both sides

(3x - 2y) ^{3}  = (11) ^{3}  \\  =  > (3x) ^{3}  - (2y) ^{3}  - 2 \times 3x \\  \times 2y = 1331 \\  =  > 27x ^{3}  - 8y ^{3}  - 12xy  \\  = 1331 \\  =  > 27 x^{3}  - 8y^{3}   - 12 \times 12 \\  = 1331 \\  =  > 27x ^{3}  - 8y ^{3}  - 144 = 1331 \\  =  > 27x ^{3}  - 8y ^{3}  = 1331  + 144 \\  =  > 27y ^{3}  - 8y ^{3}  = 1475



Thanks :))))

sw47h1: i thank u
sw47h1: but ur answer is wrong
Answered by parasramrai
4

Answer:

Step-by-step explanation:

see the attachment

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