If 3x + 2y = 12 and xy = 6, find the value of 27x^3 + 8y^3.
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Answer:
(3x+2y)^3 = 27x^3 +8y^3 + 3×3x × 2y(3x+ 2y)
(12)^3= 27x^3+8y^3+3×3×2×6×(12)
1728 = 27x^3 + 8y^3 +1296
Therefore,
27x^3 +8y^3 = 1728 - 1296
=432
Therefore answer is 432
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