if 3x +2y=12 and xy =6 find the value of 9x²+4.
Answers
Answered by
0
Step-by-step explanation:
9x²+4=(3x + 2y )² -3xy
=(12)²-3.6
=144-18
=136
:. 9x²+4=136 ans
Answered by
3
Question :
If 3x + 2y = 12 and xy = 6 , find the value of 9x² + 4y² .
Answer :
9x² + 4y² = 72
Note :
• (A + B)² = A² + B² + 2AB
• (A - B)² = A² + B² - 2AB
• (A + B)(A - B) = A² - B²
• A³ + B³ = (A + B)(A² + B² - AB)
• A³ - B³ = (A - B)(A² + B² + AB)
• (A + B)³ = A³ + B³ + 3AB(A + B)
• (A - B)³ = A³ - B³ - 3AB(A - B)
Solution :
- Given : 3x + 2y = 12 , xy = 6
- To find : 9x² + 4y² = ?
We have ;
3x + 2y = 12
Now ,
Squaring both the sides , we get ;
=> (3x + 2y)² = 12²
{ using identity (A + B)² = A² + B² + 2AB }
=> (3x)² + (2y)² + 2•3x•2y = 144
=> 9x² + 4y² + 12xy = 144
=> 9x² + 4y² + 12•6 = 144
=> 9x² + 4y² + 72 = 144
=> 9x² + 4y² = 144 - 72
=> 9x² + 4y² = 72
Hence ,
9x² + 4y² = 72
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