If 3x+2y=12 andxy=2 find the value of 9x2+4x2
Answers
Answered by
0
Given,
3x+2y=12 , xy=6
(3x+2y)^2 =12^2
=9x^2+4y^2+12xy=144
ie, 9x^2+4y^2+(12×6)=144
=9x^2+4y^2+72=144
9x^2+4y^2=144-72
=72.
3x+2y=12 , xy=6
(3x+2y)^2 =12^2
=9x^2+4y^2+12xy=144
ie, 9x^2+4y^2+(12×6)=144
=9x^2+4y^2+72=144
9x^2+4y^2=144-72
=72.
Similar questions