Question

If 3x+2y=12and xy=6,find the value of 9x^+4y^

Answer 1

Answer:

answer=72

Step-by-step explanation:

Given,

3x+2y=12 , xy=6

(3x+2y)^2 =12^2

=9x^2+4y^2+12xy=144

ie, 9x^2+4y^2+(12×6)=144

=9x^2+4y^2+72=144

9x^2+4y^2=144-72

=72.

mark me as the brainliest

Answer 2

Answer:

72

Step-by-step explanation:

xy=6-------♡

x=6/y--------☆

3x+2y=12

3(6/y)+2y=12 (From ☆)

18/y+2y=12

(18+2y^2)/y=12

18+2y^2=12y

2(y^2+9)=12y

y^2+9=6y

y^2-6y+9=0

y^2-3y-3y+9=0 (Splitting the middle term )

y(y-3)-3(y-3)=0

(y-3)(y-3)=0

y-3=0

y=3

From ☆

x=6/y

x=6/3

x=2.

9x^2+4y^2

=9(2^2)+4(3^2)

=9(4)+4(9)

=36+36

=72

HOPE THIS BRING A SMILE IN YOUR FACE