Question

If 3x-2y=13 and xy=5 find 27x^3-8y^3

Answer 1

Here 

after solving this equation

we will find that x=5 and y=1

then 27x^3-8y^3

=27*125-8*1

=3375-8

=3367

Answer 2

Step-by-step explanation:

The two equations are:

3x-2y=13 and xy=15

Now, if 3x-2y=13, then x=\frac{13+2y}{3}

Putting the value of x in xy=15, we have

(\frac{13+2y}{3})y=5

2y^{2}+13y-15=0

2y^{2}+15y-2y-15=0

On solving we get y=1, then x=5

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