Question

If 3x +2y =16 and xy=8,find the value of 27x3 +8y3

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

3712

Step-by-step explanation:

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b)$

Given

$3x + 2y = 16$

$xy = 8$

Consider

${(3x + 2y)}^{3} = 27 {x}^{3} + 8 {y}^{3} + 3xy(3x + 2y)$

${16}^{3} = 27 {x}^{3} + 9 {y}^{3} + 3 \times 8 \times 16$

$27 {x}^3 + 9 {y}^{3} = 16 \times 8 \times 32 - 8 \times 16 \times 3$

$27 {x}^{3} + 9 {y}^{3} = 3712$

Hope it helps