Question

if 3x +2y = 20 and xy =14 then find the value of 27x2 + 8y) ​

Answer 1

$\star\:\:\:\bf\large\underline\blue{Question:-}$

• If $3x+2y=20$ and $xy =14$, then find the value of $27x^{3}+8y^{3}$

$\star\:\:\:\bf\large\underline\blue{Solution:-}$

$3x + 2y = 20$

$xy = 14$

Therefore,

$27 {x}^{3} + 8 {y}^{3}$

$= {(3x)}^{3} + {(2y)}^{3}$

$= {(3x + 2y)}^{3} - 3 \times 3x \times 2y(3y + 2y)$

$= {(3x + 2y)}^{3} - 18xy(3y + 2y)$

$= {20}^{3} - (18 \times 14 \times 20)$

$= 8000 - 5040$

$= 2960$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• $27 {x}^{3} + 8 {y}^{3} = 2960$

Answer 2

Step-by-step explanation:

I have attached the answer