Question

If 3x + 2y= 23/5 and xy = 2/5. Find the value of 9x^2 + 4y^2

Answer 1

$3x \: + \: 2y = \frac{23}{5}$

$xy = \frac{2}{5}$

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$9 {x}^{2} + 4 {y}^{2}$

${(3x + 2y)}^{2} - 2 \times 3x \times 2y$

${ (\frac{23}{5}) }^{2} - 2 \times 3 \times 2 \times xy$

$\frac{529}{25} - 12 \times \frac{2}{5}$

$\frac{529}{25} - \frac{24}{5}$

$\frac{529 - 120}{25}$

$\frac{409}{25}$

$16 \frac{9}{25}$

PLEASE MARK BRAINLIEST....