If 3x -2y =5 and =6 , find the value of 27x³ - 8y³
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(8/27)x
3
−(1/8)y
3
Above terms can be written as,
((2/3x)
3
−(1/2y)
3
We know that, a
3
−b
3
=(a−b)(a
2
+ab+b
2
)
((2/3)x−1/2y)[(2/3)x+(2/3)x(1/2)y+((1/2)y)
2
]
((2/3)x−(1/2)y)[(4/9)x
2
+(xy/3)+(y
2
/4)]
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