if 3x - 2y=5 and xy =5 find 27xcube - 8ycube
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hey here is ur answer
(3x-2y)^2=5^2
9x^2+4y^2=25+2(5)
=35
27x^3-8y^3= (3x-2y)[(9x^2+4y^2-xy]
=5(35-5)
=5(30)
=150
I hope this helps u
(3x-2y)^2=5^2
9x^2+4y^2=25+2(5)
=35
27x^3-8y^3= (3x-2y)[(9x^2+4y^2-xy]
=5(35-5)
=5(30)
=150
I hope this helps u
khyathis:
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