Question

if (3x-2y) = 5 and xy = 6, find the value of (27x³-8y³)​

Answer 1

search you have to not eat as react minus 2 Y is equals to the first method and the second method and then in the second equation move by over to 6 by dividing then substitute X into the first equation and next mo2vie over 253 with the denominator of the fraction 6 and next more the Y on the left side of the equation to the right and X and X leave the equation in general form by you by letting the values equal to zero Annexe factorise the equation and solve the values of Y and substitute the values of why into the second equation and solve for x and x now we will find the values of 27 x cube minus