If 3x – 2y = 7 and xy = 3 then find the value of (3x + 2y)2.
Answers
Answered by
9
HEY......!!! here is ur answer....
Given that...
3x–2y = 7.......(1)
& xy = 3......(2)
From equation (2)
x = 3/y
On putting the value of "x" in equation (1)
=> 3(3/y)–2y = 7
=> 9–2y² = 7y....(3)
=> 2y²+7y–9 = 0
=> 2y²–2y+9y–9 = 0
=> 2y(y–1)+9(y–1) = 0
=> (y–1)(2y+9) = 0
Then required value of y = 1 & –9/2
when the value of y = 1 then x = 3/y = 3
& when the value of y = –9/2 then
x = 3/y = –2/3 <<<<<<Ans.
I hope it will be helpful for u...!!
THANK YOU....
Given that...
3x–2y = 7.......(1)
& xy = 3......(2)
From equation (2)
x = 3/y
On putting the value of "x" in equation (1)
=> 3(3/y)–2y = 7
=> 9–2y² = 7y....(3)
=> 2y²+7y–9 = 0
=> 2y²–2y+9y–9 = 0
=> 2y(y–1)+9(y–1) = 0
=> (y–1)(2y+9) = 0
Then required value of y = 1 & –9/2
when the value of y = 1 then x = 3/y = 3
& when the value of y = –9/2 then
x = 3/y = –2/3 <<<<<<Ans.
I hope it will be helpful for u...!!
THANK YOU....
Answered by
0
Answer:
x=3/y = -2/3
Step-by-step explanation:
3(3/y)-2y=7
9-2y²=7y(3)
2y²+7y-9=0
2y²-2y+9y-9=0
2y(y-1)+9(y-1)=0
(y-1)(2y+9)=0
x=3/y = -2/3 is answer
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