IF 3x-2y=8 and xy =8 then evaluate 27x^3-8y^3
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Answer:
a3-b3=(a-b) (a2+ab+b2)
(3x)3-(2y)3= (3x-2y) (9x2+4y2+6xy)
=11(9x2+4y2-12xy+18xy)
=11((3x-2y)2+18xy)
=11(121+18*12)
=11(121+216)
=11*337
=3707
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