Question

if 3x+2y=80 then find y value​

Answer 1

Could you please provide the other equation also for finding the value of both X and Y .

Answer 2

Answer:

(x+2y) = (x-2y)+80

(x+2y) = (x-2y)+80Drop the parentheses:

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20You can also try solve for x since we know the value of y:

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20You can also try solve for x since we know the value of y:(x+2y) = (x-2y)+80

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20You can also try solve for x since we know the value of y:(x+2y) = (x-2y)+80y = 20

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20You can also try solve for x since we know the value of y:(x+2y) = (x-2y)+80y = 20x+2*20 = x-2*20+80

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20You can also try solve for x since we know the value of y:(x+2y) = (x-2y)+80y = 20x+2*20 = x-2*20+80x+40 = x-40+80

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20You can also try solve for x since we know the value of y:(x+2y) = (x-2y)+80y = 20x+2*20 = x-2*20+80x+40 = x-40+80x+40 = x+40

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20You can also try solve for x since we know the value of y:(x+2y) = (x-2y)+80y = 20x+2*20 = x-2*20+80x+40 = x-40+80x+40 = x+40Subtract 40 from both sides:

(x+2y) = (x-2y)+80Drop the parentheses:x+2y = x-2y+80Add 2y to both sides:x + 4y = x + 80Subtract x from both sides:4y = 80Divide by 4:y = 20You can also try solve for x since we know the value of y:(x+2y) = (x-2y)+80y = 20x+2*20 = x-2*20+80x+40 = x-40+80x+40 = x+40Subtract 40 from both sides:x = x