If 3x+3y=12,xy=6 find 9x2+4y2
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(3x+2y)²
=9x²+4y²+6(xy) (using the identity of (a+b)²=a²+b²+2ab )
=9x²+4y²+36 ( given xy=6 )
⇒9x²+4y²= -36
=9x²+4y²+6(xy) (using the identity of (a+b)²=a²+b²+2ab )
=9x²+4y²+36 ( given xy=6 )
⇒9x²+4y²= -36
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