Question

if 3x=3y=3z and x+y+z= 27
$\sqrt{29}$
then
$\sqrt{x2 + y2 + z2}$




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Answer 1

Answer:

your question is confusing make it more understandable

Answer 2

Answer:

83.94 ~ 84

Step-by-step explanation:

x=y=z (.: 3x=3y=3z)

x+y+z=27√29

3x=27√29

x=9√29

Now,

(x+y+z)2=x2+y2+z2+2(xy+yz+xz)

:. (x+y+z)2=(27√29)2

=> x2+y2+z2+2(xy+yz+xz)=(27√29)2

=> x2+y2+z2+2(x.x+x.x+x.x)=(27√29)2 (.: x=y=z)

=> x2+y2+z2+6x2=(27√29)2

=> x2+y2+z2 = (27√29)2-6x2

=> x2+y2+z2 = (27√29)2-6(9√29)2 (.: x=y=z)

=> x2+y2+z2 = 7047

=> √x2+y2+z2 = √7047

                        = 83.94