If 3x+4;4x-8;7x+4 are in AP, find the value of x
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If x+1, 3x, and 4x+2 are in A.P., then what is x?
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What is the value of x if x+1, 3x and 4x+2 are in a.p.?
Assume these expressions are in ascending order and that they are consecutive terms of the arithmetic progression.
What is the common difference d ? Have that
d=3x−(x+1)=3x−x−1
=2x−1
and d=4x+2−3x=x+2 .
Since d=d , set these two differences equal to each other to obtain x :
2x−1=x+2⟹x=3,
and this is the answer to the problem.
The three given terms of the a.p. are then
x+1=3+1=4 ,
3x=3(3)=9 , and
4x+2=4(3)+2=12+2=14.
The common difference is d=5
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