Question

if 3x-4/(x-3)(x+a)=1 ÷x-3+2÷x+a then find the value of a​

Answer 1

Answer:

(3x-4)/(x-3)(x+a) = 1/(x-3) + 2/(x-a)

                         = [1(x-a)+2(x-3)]/ (x-3)(x-a)

(x-3)(x-a)/(x-3)(x-a)= [(x-a)+(2x-6)]/ (3x-4)

1   =  (3x -a -6)/ (3x-4)

3x-4 = 3x -a -6

-4+6 = -a

2=-a

a=-2

Step-by-step explanation: