If 3x-4y =0 and xy =12 find the value of 27x^3-64y^3
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Step-by-step explanation:
27x^3 - 64y^3 = (3x)^3 - (4y)^3
(a - b)^3 = a^3 - b^3 - 3ab(a - b)
a^3 - b^3 = (a - b)^3 - 3ab(a - b)
(3x)^3-(4y)^3 =(3x-4y)^3-36xy(3x-4y)
27x^3 - 64y^3 = 0.
Hope you understood well.
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