If 3x − 4y = 1 and xy = 6, find the value of 27x^3 − 64y^3
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Answered by
0
Answer:
Correct option is
B
665
3x−4y=5
Cubing both sides,
(3x−4y)
3
=5
3
Applying the formula,(a−b)
3
=a
3
−b
3
−3ab(a−b)
(3x)
3
−(4y)
3
−3×3x×4y×(3x−4y))=125
(3x)
3
−(4y)
3
−36×xy×(3x−4y)=125
Substituting, 3x−4y=5;xy=3
27x
3
−64y
3
−36×3×5=125
27x
3
−64y
3
=125+540=665
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Answer:
if 3x_4y=1 and xy=6 find 27x^3 _64y^3
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