Question

If 3x-4y=10 and xy=2,find the value of (9x)2 + (16y)2​

Answer 1

Step-by-step explanation:

3x-4y = 10

both side square Karne per

(3x-4y)² = 100

9x² + 16y² -24xy = 100

9x² + 16y² -24(2) = 100

9x² + 16y² = 100+48=148

Answer 2

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GIVEN-:

$3x+4y=7$

$xy=2$

FIND-:

$9x^2+16y^2=?$

SOLUTION-:

$Using-:(a+b)^2=a^2+b^2+2ab$

$(3x+4y)^2=(7)^2$

NOW,

$(3x+4y)^2=(3x)^2+(4y)^2+2(3x×4y)$

By putting values

$(7)^2=(3x)^2+(4y)^2+2(12xy)$

$49=9x^2+16y^2+24xy$

$49=9x^2+16y^2+24×2$

$49=9x^2+16y^2+48$

$49-48=9x^2+16y^2$

$1=9x^2+16y^2$

ANSWER

$1=9x^2+16y^2$