Math, asked by DHIKSHU102, 1 year ago

If 3x+4y=11 and xy=2 then the value of 27x^3 + 64y^3

Answers

Answered by HarshitMestry123

3

Answer:

1265

Step-by-step explanation:

Take cube on both sides to arrive to 27x^3+64y^3 and just substitute the values of 3x+4y=11 and xy=2

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