Question

If 3x-4y+12=0 and 3x+2y-6=0, then the area of triangle formed by the given lines and x axis is (in sq.units)​

Answer 1

Step-by-step explanation:

3x-4y+12=0

3x-4y= -12..........eq(1)

3x+2y-6=0

3x+2y=6.........eq(2)

subtract eq(1) from eq(2)

3x+2y-3x+4y=6+12

6y=18

y=3 put in eq2

3x=6-6

3x=0

x=0

area of triangle=1/2(x)(y)

=1/2(0)(3)=0