Math, asked by IamRahul3690, 1 year ago

If 3x+4y=13, xy=1, find 3x-4y

Answers

Answered by keshavmpsjaipur

5

Answer:

Step-by-step explanation:

(3x+4y)^2=169

(3x-4y)^2+48xy=169

3x-4y=√169-48=√121=11

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