If 3x - 4y = 16 and 4x + 4y = 12 then what is the value of x-y?
Answers
Answered by
2
Answer:
3x+4y=16
Squaring both sides
=>(3x+4y)
2
=256
=>9x
2
+16y
2
+2(3x)(4y)=256
=>9x
2
+16y
2
+24xy=256
=>9x
2
+16y
2
=256−24×4
=>9x
2
+16y
2
=256−96
=>9x
2
+16y
2
=160
Answered by
4
3x+4y=16
Squaring both sides
=>(3x+4y)
2
=256
=>9x
2
+16y
2
+2(3x)(4y)=256
=>9x
2
+16y
2
+24xy=256
=>9x
2
+16y
2
=256−24×4
=>9x
2
+16y
2
=256−96
=>9x
2
+16y
2
=160
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