Math, asked by tryphenaasher, 3 months ago

if 3x+4y=16 and xy=4;find the value of 9x^2+16y^3​

Answers

Answered by 123akankshajha
1

Answer:160

Step-by-step explanation:

(3x+4y)^2=(16 )^2

9x^2+16y^3​+ 24xy = 256

given xy=4

9x^2+16y^3​ = 256-96

                   =160

Answered by mamtabisht25982
1

Answer:

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Step-by-step explanation:

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