If 3x+ 4y= 16 and xy = 4. find the value of:
9x2+ 16y2
Answers
Answered by
19
Answer:
Given that ( 3x + 4y ) = 16 and xy = 4
We need to find 9x2 + 16y2.
We know that
( a + b )2 = a2 + b2 + 2ab
Consider the square of 3x + 4y :
∴ ( 3x + 4y )2 = (3x)2 + (4y)2 + 2 x 3x x 4y
⇒ ( 3x + 4y )2 = 9x2 + 16y2 + 24xy
( 3x + 4y )2 = 9x2 + 16y2 + 24xy
⇒ (16)2 = 9x2 + 16y2 + 24(4)
⇒ 256 = 9x2 + 16y2 + 96
⇒ 9x2 + 16y2 = 160
Answered by
1
3x + 4y = 16 and xy is 4
x=4 , y=1
9x2 + 16y2 = [9*4*2 = 72] + [ 16*1*2 = 32]
72+32=104
Similar questions