Question

If 3x+4y=18 and xy=6 then find the value of 27xcube +64ycube

Answer 1

Step-by-step explanation:

3x+4y=18

xy=6

27x³+64y³=?

(3x+4y)²=27x³+64y³+3xy+(3x+4y)

(18)²=27x³+64y³+18+18

324=27x³+64y³+36

27x³+64y³=324-36

27x³+64y³=288

HOPE IT WILL BE HELPFUL!