if 3x + 4y = 18 and xy = 6, then find the value of 9x² + 16y².
(A) 180 (B) 144
(C) 324 (D) 170
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0
Given
3x+4y=18 and xy=6
Value of 9x^2+16y^2
(a+b)^2=a^2+2ab+b^2
Let a=3xand b=4y
(3x+4y)^2=(3x)^2+2(3x)(4y)+(4y)^2
(3x+4y)^2-2(3x)(4y)=9x^2+16y^2
=(18)^2-24(6)
= 324-144
=180
Hence 9x^2+16y^2=180
Answer option A
3x+4y=18 and xy=6
Value of 9x^2+16y^2
(a+b)^2=a^2+2ab+b^2
Let a=3xand b=4y
(3x+4y)^2=(3x)^2+2(3x)(4y)+(4y)^2
(3x+4y)^2-2(3x)(4y)=9x^2+16y^2
=(18)^2-24(6)
= 324-144
=180
Hence 9x^2+16y^2=180
Answer option A
Answered by
3
Answer:
A option
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