Question

if {3x-4y}^3=27x^3-64y^3+ax^2y+bxy^2 then find a +b
please just tell answer no steps or solution required .

Answer 1

here is your answer OK

value of a+b
(3x+4y)3 =27x 3-64y3+ax2y+bxy2
using (a+b)
3x-4y+axy+bxy
3x-4y+a(3x)(4y)+b(3x)(4y)
3x-4y+a36xy+b48xy
value of a and b is 36 and 48

Answer 2

Just expand it.

(3x - 4y)^3 = (3x)^3 - (4y)^3 + 3×(3x)^2×(-4y) + 3×3x×(-4y)^2

= 27x^3 - 64y^3 - 108x^2y + 144xy^2

So
a = -108
b = 144

a+b = -108 + 144 = 36