if 3x-4y=6 and y=2x/3 then find valur of x
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y=2x/3
Substituting y=2x/3 on the equation 3x-4y=6
3x-4(2x/3)=6
3x-(8x)/3=6
(9x-8x)/3=6
x/3=6
x=6*3
x=18
Substituting y=2x/3 on the equation 3x-4y=6
3x-4(2x/3)=6
3x-(8x)/3=6
(9x-8x)/3=6
x/3=6
x=6*3
x=18
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