Question

if 3x+4y-7 and xy=2 find 9x+16y​

Answer 1

Answer:

3x+4y=16 and xy=4, what is the value of 9x^2+16y^2?

3x+4y=163x+4y=16

⟹(3x+4y)2=162⟹(3x+4y)2=162

⟹(3x+4y)(3x+4y)=256⟹(3x+4y)(3x+4y)=256

⟹9x2+24xy+16y2=256.⟹9x2+24xy+16y2=256.

Then xy=4xy=4

⟹9x2+24(4)+16y2=256⟹9x2+24(4)+16y2=256

⟹9x2+96+16y2=256⟹9x2+96+16y2=256

⟹9x2+16y2=256−96⟹9x2+16y2=256−96

⟹9x2+16y2=160

IF YOU WANT 9x+16y then square root boht sides

answer is 80

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Answer 2

Answer:

3x+4y-7

3x+4y =7

x+4y=7/3

x+y = 7/3+4

x+y =7/7= 1

since x+y is 1

ACCORDING TO QUESTION

9x+16y

x+16y= 1/9

x+y = 1/9 -1/16

x+y = 16+9 / 144

x+y = 25 /144

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