Question

If 3x + 4y = 7 and xy = 2. then find the value of 9x^2 + 16y^2.
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Answer 1

Answer:

hope it helps you ....

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Answer 2

Answer:

9^2 + 16y^2 = 1

Step-by-step explanation:

given that 3x +4y =7 and xy =2

Therefore

by using the identity (a+b)^2 = a^2 +2ab + b^2

(3x + 4y)^2 = 9x^2 + 16y^2 + 24xy

here putting the value of 3x +4y =7  and  xy =2

therefore

(7)^2=9x^2 +16 y^2 + 24(2)

⇒49 = 9x^2 + 16y^2 + 48

Therefore by exchanging the side of +48 will be - 48

⇒49 - 48 = 9x^2 + 16y^2

⇒9x^2 + 16y^2 = 1 (Answer)