Question

if 3x+4y =9 and xy is -2, find value of 9x^2+16y^2​

Answer 1

Answer:

Therefore, (3x+4y)² = (3x)² + (4y)² + 2(3x)(4y)

(9)² = (3x)² + (4y)² + 2(3x)(4y)

81 = 9x² + 16y² + 24xy

81 = 9x² + 16y² + 24(-2)

81 = 9x² + 16y² - 48

81+48 = 9x² + 16y²

9x² + 16y² = 129

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Step-by-step explanation: