If 3x+4y=l 2 and 4x+3Y=9then find the value of x and y
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Answer:: 3x+4y=12
4x+3y=9
now, multiplying by 4 in eq.1 and by 3 in eq.2
12x+16y=48 ---(1)
12x+9y=27 ---(2)
subtracting (2) from (1) we will get,
7y=21
then, y=3
3x+4×3=12
3x=12-12
3x=0
x=0
4x+3y=9
now, multiplying by 4 in eq.1 and by 3 in eq.2
12x+16y=48 ---(1)
12x+9y=27 ---(2)
subtracting (2) from (1) we will get,
7y=21
then, y=3
3x+4×3=12
3x=12-12
3x=0
x=0
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