Math, asked by sathish10051996, 1 year ago

If 3x - 4y + z = 7; 2x - Z + 3y = 19;
x+2y + 2z = 24, then what is the
value of z?​

Answers

Answered by Acharya01
1

Answer:

3x -4y + z = 7 ...... equ(1)

2x - z + 3y = 19 ...... equ(2)

x + 2y +2z = 24 .......equ(3)

Multiply 2 in equ(3) , we get

2x +4y+4z = (24)(2) .... equ(4)

Add equ(1) and equ(4) , we get

» 5x+5z=55

Or, x +z= 11 .......equ(5)

Multiply 2 in equ(2) , We get

4x -2z +6y = 19(2) ..........equ(6)

Multiply 3 in equ(3) ,We get

3x +6y+6z= 24(3)...........equ(7)

subtract equ(7) from equ(6)

» equ(6) - equ(7) , we get ,

» -x+8z = 72 - 38

0r, 8z - x = 34 ........equ(8)

Add equ(5) and equ(8) , we get ,

» 9z = 45

0r, z = 5

Therefore the value of Z is 5

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