If 3x - 4y + z = 7; 2x - Z + 3y = 19;
x+2y + 2z = 24, then what is the
value of z?
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3x -4y + z = 7 ...... equ(1)
2x - z + 3y = 19 ...... equ(2)
x + 2y +2z = 24 .......equ(3)
Multiply 2 in equ(3) , we get
2x +4y+4z = (24)(2) .... equ(4)
Add equ(1) and equ(4) , we get
» 5x+5z=55
Or, x +z= 11 .......equ(5)
Multiply 2 in equ(2) , We get
4x -2z +6y = 19(2) ..........equ(6)
Multiply 3 in equ(3) ,We get
3x +6y+6z= 24(3)...........equ(7)
subtract equ(7) from equ(6)
» equ(6) - equ(7) , we get ,
» -x+8z = 72 - 38
0r, 8z - x = 34 ........equ(8)
Add equ(5) and equ(8) , we get ,
» 9z = 45
0r, z = 5
Therefore the value of Z is 5
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