If 3x= 5(mod7) , then
a) x= 2(mod7)
b) x= 3(mod7)
c) x= 4(mod7)
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Answer:
c)x=4(mod7)
Step-by-step explanation:
In arithmetic modulo 7 , a multiplicative inverse of 3 is 5. This result can be obtained by writing a modulo- 7 times table for 3 until you get the product 1.
Then multiply the given congruence by 5 to get x by itself:
5×3x≡5×5 (mod 7)
and this means that the left-hand side of the congruence is
5×3x≡1x≡x(mod 7).
Then x≡25≡4+3×7
≡4+3×0≡4 (mod 7)
is a solution to the congruence.
All solutions to the given congruence have the form x=4+7t where t is an integer.
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