If (3x-58)° and( x+38)° and supplementary angle find x
Answers
Answered by
7
Answer:
3x+58°+x+38°=180°
4x+96°=180°
4x=180°-96°
x=84°/4
x=21°
Answered by
11
Answer:
we know that sum of supplementary angles is 180°
=(3x-58)°+ (x+38 ) = 180
= 3x-58+x+38 = 180
= 3x+x-58+38 = 180
4x-20=180
4x=180+20
4x=180+20
4x=200x=200/4=50
Hence, the value of x is 50°
first angle= 3x-58
=3×50-58
=150-58
=92°
second angle= 50°+38°=88°
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