Question

if 3x+5y=8
xy = 1
find:
(27x^3)+(125y^5) = ?​

Answer 1

Answer:

0

Step-by-step explanation:

27x³ -125y³ -180xy -64 when

given  3x-5y =4

or 3x-5y-4=0

Let a=3x,b=-5y and c=-4

then a+b+c=0

Then a³+b³+c³=3abc

Putting values of a,b,c

(3x)³+(-5y)³+(-4)³=3(3x)(-5y)(-4)

27x³-125y³-64=180xy

27x³-125y³-180xy-64=0