Math, asked by keziya2812, 11 months ago

If 3x+5Y=9 and 5x+3Y=7 find the value of x and y


Rujula16s: you have to add both equation (1) then subtract the equations(2) then add (1)and(2)
Rujula16s: you will get the answer
ashutosh5158: I will said that
ashutosh5158: but thank you
Rookie7: I had send u the ans
ashutosh5158: rujula
ashutosh5158: good rujula
Rujula16s: what

Answers

Answered by Rookie7
1
This is the answer Enjoy it
Attachments:
Answered by TRISHNADEVI
3

\huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \: \: SOLUTION \: \: } \mid}}}}}

\underline{ \mathfrak{ \: \: Given :- \: \: }} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \text{ 3x + 5y = 9 \: \: \: - - - - - - > (1) } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \text{5x + 3y = 7 \: \: \: - - - - - - >(2) \: } \\ \\ \underline{ \mathfrak{ \: \: To \: \: find :- \: \: }} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \text{  Value \:  of  \: x  \: and  \: y. }

\underline{ \mathfrak { \:Now,\:}} \\ \\ \rm{(1) \times 3 \implies 9x + 15y = 27 \: \: - - - - > (3)} \\ \\ \rm{(2) \times 5 \implies 25x + 15y = 35 \: \: - - - - > (4)}

 \sf{(4) - (3) \implies \: 16x = 8} \\  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf{ \implies \: x =  \frac{8}{16} } \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf{ \therefore \: \red{x = \frac{1}{2}} }

\underline{ \text{ \: Putting the value of \: \red{x} \: in eq. (1) , we get, \: }}

\: \: \: \: \: \: \: \: \: \sf{ 3 \times ( \red{\frac{1}{2}} ) + 5y = 9 }\\ \\ \sf{\implies \: \frac{3}{2} + 5y = 9 }\\ \\ \sf{\implies \: 5y = 9 - \frac{3}{2}} \\ \\ \sf{ \implies \: 5y = \frac{18 - 3}{2}} \\ \\ \sf{\implies \: 5y = \frac{15}{2}} \\ \\ \sf{ \implies \: y = \frac{15}{2} \times \frac{1}{5} } \\ \\ \: \: \: \: \: \: \: \: \: \: \sf{\therefore \: \red{ y = \frac{3}{2} }}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \boxed{  \bold{ \: \therefore \: \red{ x =  \frac{1}{2}}   \:  \: \:  \: and \: \:  \:   \: \red{ y =  \frac{3}{2}  \: }}}

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