Question

if 3x +64 = 2^6+(√3)^8 , then find x​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

x=27

Step-by-step explanation:

if

$3x + 64 = ( {2)}^{6} + {( \sqrt{3} )}^{8}$

To find the value of x,first we have to solve the powers

$3x + 64 = 64 + ( { ({ \sqrt{3}) }^{2}) }^{4} \\ \\ 3x + 64 = 64 + ( {3)}^{4} \\ \\ 3x + 64 - 64 = 81 \\ \\ 3x = 81 \\ \\ x = \frac{81}{3} \\ \\ x = 27$

Hope it helps you.