if 3x-7y=10 and xy=-1 find 9x square +49y square
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(3x-7y) =10
squaring both the sidees.
(3x-7y)^2=(10)^2
9x^2+49y^2 -42xy = 100
9x^2+49y^2 -42× (-1) = 100
9x^2+49y^2 = 100-42
9x^2+49y^2= 58
squaring both the sidees.
(3x-7y)^2=(10)^2
9x^2+49y^2 -42xy = 100
9x^2+49y^2 -42× (-1) = 100
9x^2+49y^2 = 100-42
9x^2+49y^2= 58
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