Question

if 3x-7y=10 and xy= -1. find the value of 9x^2 + 49y^2

Answer 1

= 58 Answer
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Answer 2

Solution:-

given by:-

$9 {x}^{2} + 49 {y}^{2} = {(3x - 7y)}^{2} + 42xy \\ 9 {x}^{2} + 49 {y}^{2} = {10}^{2} + 42( - 1) \\ 9 {x}^{2} + 49 {y}^{2} = 100 - 42 \\ 9 {x}^{2} + 49 {y}^{2} = 58$
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